How many grams of iron can be obtained from a 268-g sample of iron(iii) oxide?

187.44 g

Explanation:

Calculation of the moles of as:-

Mass = 268 g

Molar mass of iron(III) oxide = 159.69 g/mol

The formula for the calculation of moles is shown below:

Thus,

According to the formula, 1 mole of iron(III) oxide has 2 moles of iron.

Also,

1.67825 mole of iron(III) oxide has moles of iron.

Moles of iron = 3.3565 moles

Molar mass of iron = 55.845 g/mol

Mass=Moles*Molar mass = = 187.44 g

187.44 g of iron can be obtained from a 268-g sample of iron(III) oxide.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

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