You use 4.98 g of na2so4, how many grams of barium sulfate are produced?

na2+ba(no3)2= ?

Mass of barium sulfate = 8.17 g

Explanation:

Given data:

Mass of sodium sulfate = 4.98 g

Mass of barium sulfate produced = ?

Solution:

Na₂SO₄ + Ba(NO₃)₂    →   BaSO₄ + 2NaNO₃

Moles of sodium sulfate:

Number of moles = mass/molar mass

Number of moles =4.98 g / 142.04 g/mol

Number of moles = 0.035 mol

Now we will compare the moles pf sodium sulfate and with barium sulfate.

                            Na₂SO₄               :            BaSO₄

                                1                       :              1

                              0.035                :          0.035

Mass of barium sulfate:

Mass = number of moles × molar mass

Mass =   0.035 mol ×233.4 g/mol

Mass = 8.17 g

може ли да зареждате повече информация, моля