Show the calculation of the freezing point of a solution made by dissolving 12.6 grams of the electrolyte nano3 in 200 grams of water. kf for water is 1.86 and the fp of pure water is 0oc.

The freezing point of the solution is

Explanation:-

Depression in freezing point is given by:

= Depression in freezing point

i= vant hoff factor = 2 (for which dissociates to give two ions )

= freezing point constant =

m= molality

Weight of solvent (water)= 200 g = 0.2 kg

Molar mass of electrolyte =  85 g/mol

Mass of electrolyte added = 12.6 g

The freezing point of the solution is

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.