Suppose you need 7.0 m of grade 70 tow chain, which has a diameter of 38" and weighs , 2.16/kgm to tow a car. how would you calculate the mass of this much chain?

Answer : The mass of 7.0 m chain is, 15.12 kg

Explanation :

As we are given that,

The weight of the chain per unit length = 2.16 kg/m

Now we have to determine the mass of chain for 7.0 m length.

As, the mass of 1 m length of chain = 2.16 kg

So, the mass of 7.0 m length of chain =

                                                                = 15.12 kg

Therefore, the mass of 7.0 m chain is, 15.12 kg

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2