In the following reaction, how many liters of o2 will produce 43.62 liters of co2 at stp? c3h8 5 o2 3 co2 4 h2o

72.7 L

Explanation:

As can be seen from the balanced chemical equation:

3 moles of carbon dioxide are produced by 5 moles of oxygen.

According to avogadro's law, 1 mole of every gas occupies 22.4 L at STP.

of carbon dioxide are produced by of oxygen at STP

Thus 43.62 L of carbon dioxide are produced by = of oxygen at STP

Thus 72.7 liters of oxygen will produce 43.62 liters of carbon dioxide at STP.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.