What is the mass of metallic silver produced by a 1.50
ampcurrent passed through a solution of silver nitrate for
20minutes?

The mass of metallic silver produced by a 1.50

amp current passed through a solution of silver nitrate for  20 minutes is 2.0 g

Explanation:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains number of particles.

We know that:

Charge on 1 electron =

Charge on 1 mole of electrons =

To calculate the time required, we use the equation:

where,

I = current passed = 1.50 A

q = total charge = ?

t = time = 20 minutes = 1200 s   (1min=60 s)

Putting values in above equation, we get:

According to stoichiometry:

1 mole of electrons deposit = 108 g of silver

i.e 96500 C of electricity deposit = 108 g of silver

Thus 1800 C  of electricity  deposit = g of silver

The mass of metallic silver is 2.0 g