Calculate the kinetic energy of a 107, mg raindrop moving at a speed of 4.7- round your answer to 2 significant digits.

1.2 × 10⁻³ J

Explanation:

Given data

We can determine the kinetic energy of the raindrop using the following expression.

K = 1/2 × m × v²

K = 1/2 × 1.07 × 10⁻⁴ kg × (4.7 m/s)²

K = 1.2 × 10⁻³ J

The kinetic energy of the raindrop is 1.2 × 10⁻³ J.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g