Calculate the partial pressure of the co2 in the expired air at its peak, assuming 1 atm pressure and a body temperature of 37∘c .

P2= 45.50 atm

Explanation:

If the amount of gas in the tanks remains same we use the equation P1T1=P2T2

40 x 281.15 = P2 x 247.15

P2= 45.50 atm

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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