1. if 22 l of methane (ch4) gas burns (combustion), how many moles of oxygen will
be needed for complete combustion?
ch4 + o2  co2 + h2o

2. acid rain is produced when sulfur trioxide reacts with water in a composition
reaction. if 15 l of sulfur trioxide is present in the air how many moles of sulfuric
acid are produced?
_ so3 + _ h2o ->

3. if calcium chlorate is heated it decomposes into calcium chloride and oxygen gas.
how many liters of oxygen can be produced form heating 34 moles of calcium
carbonate?

4. sulfur and oxygen combine to form sulfur dioxide in a composition reaction. how
many grams of sulfur are required to react with 17 l of oxygen?
s + o2  so2

5. 4. by running a direct current through water, it can be decomposed it into its elements. how many liters of hydrogen gas can be produced from 1500 g of water?
h2o ->

6. hydrogen and chlorine can be combined to form hydrochloric acid. if you reacted 6
liters of hydrogen with chlorine how many grams of acid will be produced?

7. when glucose (c6h12o6) undergoes combustion with oxygen it produces water and carbon dioxide. how many liters of carbon dioxide will be produced if glucose reacts with 45 liters of oxygen?
c6h12o6 + o2 -> h2o + co2

8. how many liters of nitrogen monoxide can be made using 18 liters of oxygen in the
following composition reaction?
n2 + o2 ->

9. how many liters of carbon dioxide are produced when 10 liters of propane (c3h8)
undergoes complete combustion? (assume stp)

1) 1.964 moles of O2

2) 0.670 moles of H2SO4

3)  2284.8 liters of oxygen

4) 24.3 grams of S

5) 1864.6 L of hydrogen gas

6) 19.54 grams of HCl

7) 45.0 L of CO2 produced

8) 36.0 L of NO

9) 30L of CO2

Explanation:

1. If 22 L of methane (CH4) gas burns (combustion), how many moles of oxygen will  be needed for complete combustion?

Step 1: The balanced equation:

CH4 + 2O2 → CO2 + 2H2O

Step 2: Calculate moles of CH4

Since 22.4 L = 1.0 mol

22.4L = 0.982 moles of CH4

Step 3: Calculate moles of O2 needed

For 1 mol CH4 we need 2 moles of O2 to produce 1 mol of CO2 and 2 moles of H2O

For 0.982 moles of CH4 we need 2*0.982 = 1.964 moles of O2

2. Acid rain is produced when sulfur trioxide reacts with water in a composition  reaction. If 15 L of sulfur trioxide is present in the air how many moles of sulfuric  acid are produced?

Step 1: The balanced equation

SO3(g) + H2O(l) → H2SO4(aq)

Step 2: Calculate moles of SO3

22.4 L = 1 mol

15.0 L = 0.670 moles

Step 3: Calculate moles of H2SO4

For 1 mol of SO3 we need 1 mol of H2O to produce 1 mol of H2SO4

For 0.670 moles of SO3 we will produce 0.670 moles of H2SO4

3. If calcium chlorate is heated it decomposes into calcium chloride and oxygen gas.

How many liters of oxygen can be produced form heating 34 moles of calcium  carbonate?

Step 1: The balanced equation

Ca(ClO3)2  → CaCl2 + 3O2

Step 2: Calculate moles of O2

For 1 mol of Ca(ClO3)2 consumed, we produce 1 mol of CaCl2 and 3 moles of O2

For 34 moles of Ca(ClO3)2 consumed, we'll have 3*34 = 102 moles of O2

Step 3: Calculate volume of oxygen

1 mol = 22.4 L

102 moles = 22.4 * 102 = 2284.8 liters of oxygen

4. Sulfur and oxygen combine to form sulfur dioxide in a composition reaction. How  many grams of sulfur are required to react with 17 L of oxygen?

Step 1: The balanced equation

S + O2 → SO2

Step 2: Calculate number of moles of O2

22.4 L = 1 mol

17.0 L =  0.759 moles of O2

Step 3: Calculate moles of S

For 1 mol of S we need 1 mol of O2 to produce 1 mol of SO2

For 0.759 moles of O2 we need 0.759 moles of S

Step 4: Calculate mass of S

Mass of S = moles S * molar mass S

Mass of S =  0.759 moles * 32.065 g/mol = 24.3 grams of S

5. By running a direct current through water, it can be decomposed it into its elements. How many liters of hydrogen gas can be produced from 1500 g of water?

Step 1: The balanced equation

2H2O → 2H2 + O2

Step 2: Calculate number of moles of water

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 1500 grams / 18.02 g/mol = 83.24 moles

Step 3: Calculate moles of H2

For 2 moles of H2O we'll have 2 moles of H2 and 1 mol of O2

For 83.24 moles of H2O we'll have 83.24 moles of H2

Step 4: Calculate volume of H2

1 mol = 22.4 L

83.24 moles = 22.4 * 83.24 = 1864.6 L of hydrogen gas

6. Hydrogen and chlorine can be combined to form hydrochloric acid. If you reacted 6  liters of hydrogen with chlorine how many grams of acid will be produced?

Step 1: The balanced equation

H2 + Cl2 → 2HCl

Step 2: Calculate moles of H2

22.4 L = 1 mol

6.0 L = 0.268 moles of H2 (Suppose H2 is the limiting reactant)

Step 3: Calculate moles of HCl

For 1 mol of H2 we need 1 mol of Cl2 to produce 2 moles of HCl

For 0.268 moles of H2 we'll have 2*0.268 = 0.536 moles of HCl

Step 4: Calculate mass of HCl

Mass HCl = moles HCl * molar mass HCl

Mass HCl = 0.536 * 36.46 g/mol

Mass HCl = 19.54 grams of HCl

7. . When glucose (C6H12O6) undergoes combustion with oxygen it produces water and carbon dioxide. How many liters of carbon dioxide will be produced if glucose reacts with 45 liters of oxygen?

Step 1: The balanced equation

C6H12O6 + 6O2 → 6CO2 + 6H2O

Step 2: Calculate moles of oxygen

22.4 L = 1 mol

45.0 L = 2.01 moles O2

Step 3: Calculate moles of CO2

For 1 mol of glucose we need 6 moles of O2 to prodcue 6 moles of CO2 and 6 moles of H2O

For 2.01 moles of O2 consumed we'll have 2.01 moles of CO2 produced

Step 4: Calculate liters of CO2 produced

1 mol = 22.4 L

2.01 moles = 45.0 L of CO2 produced

8. How many liters of nitrogen monoxide can be made using 18 liters of oxygen in the  following composition reaction?

Step 1: The balanced equation:

N2 + O2 → 2NO

Step 2: Calculate number of moles of O2

22.4 L = 1.0 mol

18.0 L = 0.804 moles O2

Step 3: Calculate moles of NO

For 1 mol of N2 we need 1 mol of O2 to produce 2 moles of NO

For 0.804 moles of O2 we need 2*0.804 = 1.608 moles of NO

Step 4: Calculate volume of NO

1 mol = 22.4 L

1.608 moles = 22.4 * 1.608 = 36.0 L of NO

9. How many liters of carbon dioxide are produced when 10 liters of propane (C3H8)  undergoes complete combustion? (assume STP)

Step 1: The balanced equation

C3H8 + 5O2 → 3CO2 + 4H2O

Step 2: Calculate moles of propane

22.4 L = 1.0 mol

10.0 L = 0.446 moles of propane

Step 3: Calculate moles of CO2

1 mol of propane consumed needs 5 moles of O2 to produce 3 moles of CO2 and 4 moles of H2O

For 0.446 moles of propane we'll have 3*0.446 = 1.338 moles of CO2

Step 4: Calculate volume of CO2

1 mol = 22.4 L

1.338 moles = 22.4 *1.338 = 30L of CO2

the answer would be a

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3