C). if 0.5 mole of oxygen reacted with hydrogen (h2), how many mole of water (h20) was produced
from the reaction?

1 mol of water is produced in those conditions.

Explanation:

The reaction to produce water between H₂ and O₂ is this:

2H₂  +  O₂  →  2H₂O

We don't have the amount of hydrogen, so we have to think that is in excess.

Let's work with oxygen.

Ratio is 1:2

For 0.5 mole of oxygen, I will make the double of moles of water.

1.0 mol of water will be produced.

Explanation:

Step 1: Data given

Number of moles of oxygen (O2) = 0.5 moles

Step 2: The balanced equation

2H2 + O2 → 2H20

Step 3: Calculate moles of water (H20)

For 2 moles of H2 consumed, we need 1 mol of O2 to produce 2 moles of water (H2O)

For 0.5 moles of oxygen (O2) we'll have 2*0.5 = 1.0 moles of water (H20) produced

1.0 mol of water will be produced.

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i  

lol for the pointsss