If 80 grams of al and 80 grams of fe2 o3 are combined, what is the maxium number of moles of fe that can be produced?

The maximum number of moles of Fe that can be produced is 1 mol

Explanation:

The reaction is this:

2Al + Fe₂O₃  →  2Fe  +  Al₂O₃

Moles of Al = Mass of Al / Molar mass Al

80 g / 26.98 g/m = 2.96 moles

Mol of Fe₂O₃ = Mass of Fe₂O₃ / Molar mass Fe₂O₃

80 g / 159.7 g/m = 0.500 moles

For sure, with the naked eye, the limiting reagent is the Fe₂O₃ .

1 mol of oxide, produces 2 mol of Fe

So, 0.5 mol of oxide, will produce 1 mol of Fe

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

answermeridional ;