Acylinder with a movable piston contains a fixed amount of gas at a constant pressure. initially, the cylinder contains 0.25 liters of air at 0 degrees celsius. when the temperature is increased to 35 degrees celsius, the air will occupy what volume?
a. 0.28 l

b. 0.88 l

c. 8.75 l

d. 35.25 l

a. 0.28 L

Explanation:

At constant pressure and number of moles, Using Charle's law  

Given ,  

V₁ = 0.25 L

V₂ = ?

T₁ = 0 °C

T₂ = 35 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (0 + 273.15) K = 273.15 K  

T₂ = (35 + 273.15) K = 308.15 K  

Using above equation as:

New volume = 0.28 L

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explanation:

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