If 5.0 grams of sucrose, c12h22o11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting solution?

Answer : The boiling point of the resulting solution is,

Explanation :

Formula used for Elevation in boiling point :

or,

where,

= boiling point of solution = ?

= boiling point of water =

= boiling point constant  =

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

= mass of solute (sucrose) = 5.0 g

= mass of solvent (water) = 10.0 g

= molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

Therefore, the boiling point of the resulting solution is,

points

explanation: