Astudent has 2.99 g of potassium permaganate. how many ml of a .532 m solution can the student make?

how does one solve this?

Explanation:

you must be know the formula of potassium permaganate is KMnO₄

now you have already in question 2 things ,

1. the molarity of solution = 0.532 M

2. the mass of KMnO₄ = 2.99 g

the molarity law is  M = moles of solute  / volume (L)

so use this equation to calculate the volume in liter and convert the result to milliliter.

( if the mass unit is gram (g) = volume must be litter (L) and if the mass unit is milligram = volume must be milliliter (ml) )

** first you must use this equation to calculate how many moles do you have in KMnO₄

number of moles = mass (g) / molecular weight "MW" (g/mole )  

now you have 2.99 g ( Mentioned in Question )

and you can calculate MW if you now the Chemical formula

so we have KMnO₄  

Mw for KMnO₄  = 39 + 55 + 4x16 = 158 g/mole

**( K=39 , Mn=55 , O= 16 )

so number of moles = 2.99 / 158 = 0.018 = 0.02 moles

and if you go back to the molarity law : 

Molarity = moles of solute  / volume (L)

so  0.532 = 0.02  / volume (L)

Volume (L) = 0.532 x 0.02 = 0.01064 L

convert to ml =  0.01064 x 1000 = 10.64 ml

Good Luck

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.