Which volume of 0.10m naoh exactly neutralizes 15.0 milliliters of 0.20m hno3?

The balanced chemical reaction is:

HNO3 + NaOH = NaNO3 + H2O

We are given the amount and concentration of the reactants. The values given will be the starting point.

0.20 mol /L HNO3 (.015 L) (1 mol NaOH / 1 mol HNO3) = 0.003 mol NaOH

0.003 mol NaOH / 0.10 mol/ L NaOH = 0.03 L NaOH or 30 mL NaOH

Sorry i dont understand the question can you rephase it?

It idk haha what are we doing?