Scientists have observed huge bubbles of gas ejecting from the sun. which of these events would most likely occur due to this solar condition? (2 points) question 2 options: 1) decrease in wind velocity 2) decrease in the gravitational force 3) increase in the average temperature of earth 4) increase in the amount of helium in the atmosphere

3) increase in the average temperature of Earth

Explanation:

Coronal mass ejections or CME is the phenomena described as "Scientists have observed huge bubbles of gas ejecting from the sun". Whilst CMEs can happen alongside solar flares, it is also important to know that they can occur by themselves (independently). Solar flares refers to the abrupt release of energy kept in twisted magnetic fields caused by explosions on the Sun.

When these solar flares hit the earth, the gases (gas molecules) in the upper atmosphere such as nitrogen and water vapor are broken up and freed. This new gases then react with molecules in the ozone layer and reduce its layer. Consequently, the result is that there is increase in the average temperature of Earth.

Hence, option 3 is the event most likely to occur due to this solar condition

a. a primary source combines several different accounts of an event. b. a primary source generally benefits from having been written after an event.

explanation:

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years