Temperatures in june in the paradise city are distributed nearly normally with mean 82 degrees and standard deviation 6 degrees f. which of the following temperatures would be considered unusual?

a. 89.2
b. 75.4
c. 79
d. 86.2
e. 95.8

E

Explanation:

We are given, mean μ = 82°

standard deviation σ = 6°

For each of the options x, we will evaluate their respective z-scores given by

z-score = (x - μ)/σ

Hence, for 89.2, z = (89.2 -82) / 6 = 1.2

For 75.4, z = (75.4 - 82) / 6 = -1.1

For 79, z =(79 - 82) / 6 = -0.5

For 86.2, z = (86.2 - 82) / 6 = 0.7

For 95.8, z = (95.8 - 82) / 6 = 2.3

The z score of temperature greater than 2 and less than -2 are considered as unusual

This is the case with temperature 95.8°. Hence, the temperature will be considered unusual.

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