Ice floats on water. for most other substances, however, the solid sinks in the liquid. classify each of these statements based on whether they describe water or most other substances. a. in a phase diagram the solid-liquid coexistance line has a negative slope. b. in a phase diagram the solid-liquid coexistance line has a positive slope. c. the solid is more dense than the liquid. d. the solid is less dense than the liquid. e. the molecules are closest in the solid phase. f. the molecules are closest in the liquid phase. g. high pressure will cause the solid to become liquid. h. high pressure will cause the solid to become liquid.

True for water: a. In a phase diagram the solid-liquid coexistance line has a negative slope. d. the solid is less dense than the liquid. f. the molecules are closest in the liquid phase. g. Higher pressure will cause the solid to become liquid.

True for most other substances: b. In the phase diagram the solid-liquid coexistance line has a positive slope. c. the solid is more dense than the liquid. e. the molecules are closest in the solid phase. h. higher pressure will cause the liquid to become solid.

Explanation:

Liquid water is usually more dense than the solid ice. This is in contrast to most other substances. In addition, the phase diagram of liquid water is different from those of other substances because of the signs of their slopes. The presence of high pressure can change ice to liquid water while for other substances the presence of high pressure will change liquid to solid.

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%