The explosion of 2.00 mol of solid trinitrotoluene (tnt; c7h5n3o6) with a
volume of approximately 274 ml produces gases with a volume of 448 l at room temperatur and 1.0 atm pressure. how much pv work in kilojoules is done during the explosion?
2 c7h5n3o6(> 12 co(g) + 5 h2(g) + 3 n2(g) + 2 c(s)

-45.37 kJ

Explanation:

The work done for the explosion of 2 moles of TNT can be determined by taking the product of the pressure and change in volume. In addition, the explosion of a substance is endothermic in nature. Thus, we have the equation for work done as:

W = P*dV

Where:

W = work done (L*atm)

P = pressure (atm) = 1.0 atm

dV = change in volume (L) = 0.274 - 448 = -447.726 L

Therefore,

W = 1.0 * (-447.726) = -447.726 L*atm

1 L*atm is equivalent to 101.325 J

Thus, the work done in kJ is:

-447.726*101.325/1000 = -45.37 kJ

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