Achemistry student needs of -ethyltoluene for an experiment. he has available of a w/w solution of -ethyltoluene in benzene. calculate the mass of solution the student should use. if there's not enough solution, press the "no solution" button. be sure your answer has the correct number of significant digits.

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explanation:

488479

rvmoo+478)9.68

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

it is a solid

explanation: