Draw a resonance structure, complete with all formal charges and lone (unshared) electron pairs, that shows the resonance interaction of the acetoxy with the ortho position in phenyl acetate. i. you do not have to consider stereochemistry. ii. include all valence lone pairs in your answer. iii. in cases where there is more than one answer, just draw one.

see explanation

Explanation:

the pheny acetate, is an ester in an aromatic ring. We have the bencene and in one of the carbon, it's the acetate ion.

Now, the acetate has two oxygens with at least one pair of electrons that are available to do resonance in all the structure of the aromatic ring, because the aromatic ring has double bonds all over the ring, and can have resonance with the electrons of the oxygens.

This resonance structure can be in all the ring, or just in some positions of the ring. In this case the ortho position, which is the carbon 2. So we only can have two or three resonance structure. See the picture below for resonance.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j