Choose the aqueous solution that has the highest boiling point. these are all solutions of nonvolatile solutes and you should assume ideal van't hoff factors where applicable. a. 0.100 m k2so4 b. 0.100 m lino3 c. 0.200 m c3h8o3 d. 0.060 m na3po4 e. they all have the same boiling point.

0.100 m

Explanation:

Elevation in boiling point is given by:

= Elevation in boiling point

i= vant hoff factor

= boiling point constant

m= molality

1. For 0.100 m

, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be

2. For 0.100 m

, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be

3.  For 0.200 m

, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be

4. For 0.060 m

, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be

Thus as concentration of solute is highest for , the elevation in boiling point is highest and thus has the highest boiling point.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g