The equilibrium constant is given for one of the reactions below.

determine the value of the missing equilibrium constant.
2 hd(g) ⇌ h2(g) + d2(g) kc = 0.28
2 h2(g) + 2 d2(g) ⇌ 4 hd(g)

12.7551

Explanation:

The given chemical equation follows:

The equilibrium constant for the above equation is 0.28.

We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '2', the equilibrium constant of the reverse reaction will be the square of the equilibrium constant  of initial reaction.

The value of equilibrium constant for reverse reaction is:

Hence, the value of equilibrium constant for reverse reaction is 12.7551.

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