Determine the molar solubility (in m to two decimal places) of solid cobalt(ii) hydroxide ksp=5.92x10^-15 when dissolved in:

a) water (at 25 degree c)

b) an aqueous solution containing 0.1 m naoh (at 25 degree c)

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer