Chemistry, 19.12.2019 20:31, harshakayla02
Ascientist measures the standard enthalpy change for the following reaction to be -190.0 kj : hcl(g) + nh3(g) nh4cl(s) based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of nh4cl(s) is kj/mol.
Answers: 3
is -328.4 kJ/mol![\Delta H_{rxn}=\sum [n\times \Delta H_f_{(products)}]-\sum [n\times \Delta H_f_{(reactants)}]](/tpl/images/0426/4202/192b9.png)
![\Delta H_{rxn}=[(1\times \Delta H_f_{(NH_4Cl(s))})]-[(1\times \Delta H_f_{(NH_3(g))})+(1\times \Delta H_f_{(HCl(g))})]](/tpl/images/0426/4202/589ac.png)
![-190.0=[(1\times \Delta H_f_{(NH_4Cl(s))})]-[(1\times (-46.1))+(1\times (-92.30))]\\\\\Delta H_f_{(NH_4Cl(s))}=-328.4kJ/mol](/tpl/images/0426/4202/9648b.png)
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Ascientist measures the standard enthalpy change for the following reaction to be -190.0 kj : hcl(g...
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