16. what is the percent composition of a compound that contains 36.03 g of c and 8.06 of h

The percentage composition of the compound is 81.72% of C and 18.28% of H.

Explanation: Percentage composition is the percentage by mass of each element in a compound. It is the ratio of an amount of each element to the total amount of individual elements in a compound, which is then multiplied with 100.

Since the compound above contains only carbon and hydrogen, we will have to find the sum of their masses.

Given 36.03g of Carbon and 8.06g of hydrogen,

36.03g + 8.06g = 44.09g of the compound

%composition= gram of element/gram of compound × 100

%C = 36.03/44.09 × 100

%C= 0.8172 × 100

℅C= 81.72%

Likewise for H

%H= 8.06/44.09 × 100

%H= 0.1828 × 100

%H= 18.28%

Therefore, the compound can be said to contain 81.72% of C and 18.28% of H

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.