Areaction is non-spontaneous at any temperature whendelta h is negative and delta s is positivedelta h is positive and delta s is negativedelta h is negative and delta s is negativedelta h is positive and delta s is positive

Delta H is positive and Delta S is negative

Explanation:

The expression for the standard change in free energy is:

Where,  

is the change in the Gibbs free energy.

T is the absolute temperature. (T in kelvins)

is the enthalpy change of the reaction.

is the change in entropy.

For a reaction to be non-spontaneous,

So,

To be the above equation satisfied, the conditions are:-

and

Thus, answer is:- Delta H is positive and Delta S is negative

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.