Electricity is the flow of electrons. the following questions relate to how electricity is quantified.1. electrons are charged particles. the amount of charge that passes per unit time is calleda. potentialb. currentc. voltage2. the driving force for the electrons (i. e., the reason they are flowing in the first place) is measured bya. chargeb. currentc. potential3. charge is measured ina. amperes (a)b. coulombs (c)c. joules (j)d. volts (v)4. current is measured ina. amperes (a)b. coulombs (c)c. joules (j)d. volts (v)5. potential is measured ina. amperes (a)b. coulombs (c)c. joules (j)d. volts (v)

The correct option are:

1.  (b) current

2. (c) potential

3.  (b) coulombs (C)

4.  (a) amperes (A)

5.  (d) volts (V)

Explanation:

Electric charge is a property of a particle, like electron and proton. The subatomic particles, electrons and protons are negatively and positively charged particles, respectively.

The electric charge of a particle can be measured in coulomb, denoted by C.

Current or electric current is defined as the net flow of the electric charges through a given region, per unit time. Electric current can be measured in ampere, denoted by A.

Potential or Electric potential is described as the work done to displace the electric charges from one point to another. Potential is the driving force for the movement of charges and can be calculated in volt, denoted by V.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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