Hcl(aq) + naoh(aq) -> nacl(aq) + h2o(l) a student was given the task of titrating a .20 ml sample of 0.10 m hcl(aq) with 0.10 m naoh(aq).

according to the equation for the reaction if the amt. of reactants is halved, how does this affect the amount of h2o(l) produced in the reaction? (urgent pls)