A2.00 l sample of gas at 35c is to be heated at constant pressure until it reaches a volume of 5.25 l. to what kelvin temperature must this sample be heated?

When the volume increased from 2.00 to 5.25L the new temperature is 808.9 K ( =535.75 °C)

Explanation:

Step 1: Data given

The initial volume of the sample = 2.00 L

The initial temperature = 35 °C =  308 K

The increased volume = 5.25 L

Pressure = constant

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒ with V1 = the initial volume = 2.00 L

⇒ with T1 = the initial volume = 308 K

⇒ with V2 = the new volume = 5.25 L

⇒ with T2 = the new temperature

2.00 / 308 = 5.25 / T2

0.00649 = 5.25/T2

T2 = 5.25/ 0.00649

T2 = 808.9 K

When the volume increased from 2.00 to 5.25L the new temperature is 808.9 K ( =535.75 °C)

108

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