How many liters are in 2.5 moles of chlorine gas?

Volume of the chlorine gas is 0,056 m³.

Explanation:

p × V = n × R ×T

p = 101325 Pa

n = 2,5 moles

R = 8,31446 J K⁻¹ moles⁻¹

T = 273,15 K

(standard conditions)

V = ( n × R × T ) / p = ( 2,5 moles × 8,31446 J K⁻¹ moles⁻¹ × 273,15 K) / 101325 Pa

V = 0,056 m³

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"