Will give brainliesta weather balloon with a volume of 14.8 m3 was launched from a a research station at anderson air force base in guam at 1 atm where the temperature was 24 °c. at an altitude of 11 000 m the temperature dropped to -56 °c and the volume had increased to 50.0 m3.
what was the pressure of the balloon at that altitude?

6.9 atm

0.216 atm

2.56 atm

43.0 atm

1.34 atm

P₂ = 0.216 atm

Explanation:

Given data:

Initial volume = 14.8 m³ or 14.8 L

Initial pressure = 1 atm

Initial temperature = 24 °C (24 +273 = 297 K)

Final temperature = -56°C (-56+273 = 217 K)

Final volume = 50.0 m³

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ = 1 atm. 14.8 L. 217 K / 297 K. 50.0 L

P₂ = 3211.6 atm/14850

P₂ = 0.216 atm

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