At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant, kc. 3 a ( g ) + 2 b ( g ) − ⇀ ↽ − 4 c ( g ) k c = 2.93 × 10 29 if, at this temperature, 2.30 mol of a and 3.90 mol of b are placed in a 1.00 l container, what are the concentrations of a, b, and c at equilibrium?

The equilibrium concentration of A, B and C are 0.02 M, 2.38 M and 3.04 M respectively.

Explanation:

We are given:

Initial moles of A = 2.30 moles

Initial moles of B = 3.90 moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

So, concentration of A =

Concentration of B =

The given chemical equation follows:

Initial:          2.30       3.90

At eqllm:   2.30-3x   3.90-2x    4x

The expression of for above equation follows:

We are given:

Putting values in above expression, we get:

So, the equilibrium concentration of A =

The equilibrium concentration of B =

The equilibrium concentration of C =

Hence, the equilibrium concentration of A, B and C are 0.02 M, 2.38 M and 3.04 M respectively.

i believe the answer is c. "baking" is the gerund, while "baking blueberry muffins" would be the gerund phrase. hope this ! : )

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.