How many moles of ethane (c2h6) would be needed to react with 62.3 grams of oxygen gas?

unbalanced equation: c2h6 + o2 → co2 + h2o

show, or explain, all of your work along with the final answer.

The combustion of ethane is expressed in the balanced reaction C2H6 + 3.5O2= 2CO2 + 3 H2O. Given the mass of oxygen gas, we get the moles of ethane needed by converting this mass to mole (dividing my 32 g/mol), then multiply by 1/3.5 (stioch ratio) and the molar mass of ethane (30 g/mol). The answer is 16.69 grams ethane. 

Most likely a is the answer - because  you generate   38 atp's but also consume an atp.   each atp gives approx. less than 4 kcal so probably a is the closest answer.

Because it was a dramatically big guy