The ksp of copper(ii) ferrocyanide (cu2[fe(cn)6]) is 1.3 × 10−16 at 25°c. determine the potential of a concentration cell in which one half-cell consists of a copper electrode in 1.00 m copper(ii) nitrate, and the other consists of a copper electrode in a saturated solution of cu2[fe(cn)6].

ferrocyanide, ([fe(cn)6]4−), is a complex ion.

Explanation:

Expression for of the given reaction is as follows.

Let us assume that the concentration of given species is "s". As the value of is given as .

                     s =

Therefore, concentration of will be calculated as follows.

            = 2s

                         =        

                        = M

Now, we will calculate the value of as follows.

                            =

                            = 0.1535 V

Thus, we can conclude that the potential of given cell is 0.1535 V.

- "the choice that is not an indicator of a chemical change is "state of matter changes". more common than not, chemical reactions produce energy in the form of light or heat. along with energy, they also produce a new substance called the product that could be in any state of matter (solid, gas, or liquid)."