The density of solid ag is 10.5 g/cm3. how many atoms are present per cubic centimeter of ag?

as a solid, ag adopts a face-centered cubic unit cell. how many unit cells are present per cubic centimeter of ag?

what is the volume of a unit cell of this metal?

what is the edge length of a unit cell of ag?

break it down to me step-by-step, so i can understand it.

Unit cells which are present per cubic centimeter of Ag =

Volume =

Edge length =

Explanation:

(a)

Given that:-

The density of the solid Ag = 10.5 g/cm³

Molar mass of silver = 107.8682 g/mol

So, Moles present per cm³ of Ag = =0.0973 mol/cm³

Also, 1 mole = atoms.

So,

Atoms present per cm³ of Ag =

Thus, answer =

In FCC, the number of atoms  in the unit cell = 4 unit cells

So,

Unit cells which are present per cubic centimeter of Ag =

Unit cells which are present per cubic centimeter of Ag =

(b)

The reciprocal of the unit cell/cm³ is the volume of the unit cell.

So,

Volume =

(c)

Also, Volume =

Thus, edge length = =

Edge length =

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2