What is your question? high school chemistry 5+3 pts to ensure that the air in the shuttle remains free of excess co2, engineers test the air-purification system. they combine 1.000 × 103 g lioh with 8.80 × 1 02 g co2. the reaction produces 3.25 × 102 g h2o. what is the limiting reactants in this test reaction

The balanced reaction is:

2LiOH + CO2 = Li2CO3 + H2O

We are given the amount of the reactants to be reacted. This will be the starting point of our calculations. To determine the limiting reactant, we convert the amounts from grams to moles.

1.000 × 10^3 g LiOH  (1 mol / 25.95 g) = 38.54 mol LiOH

8.80 × 10^2 g CO2 ( 1mol / 44.01 g) = 20.00 mol CO2

From the balanced reaction, the molar ratio of the reactants is 2:1. This means that every two mole of lithium hydroxide, 1 mole of carbon dioxide is needed. It is clear that, from the given amounts, CO2 is the limiting reactant.

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.