Aballoon filled with air has a volume of 0.500 l at 25.0 ºc and an internal pressure of 1.20 atm. what will the volume of the balloon be after it is placed in a freezer at –10.0 ºc if the internal pressure does not change?

0.441 L

Explanation:

At constant pressure, Using Charle's law  :-

Given ,  

V₁ = 0.500 L

V₂ = ?

T₁ = 25.0 °C

T₂ = -10.0 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (25 + 273.15) K = 298.15 K  

T₂ = (-10 + 273.15) K = 263.15 K  

Using above equation as:

New volume = 0.441 L

it is stable as it is in group 0 which have full outer shells of electrons

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.