If we mix 25 grams of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chloride be?

the equation to solve it is nabr + kcl —> nacl + kbr

Theoretical yield of sodium chloride = 14.04 g

Explanation:

Given data:

Mass of sodium bromide = 25 g

Theoretical yield of sodium chloride = ?

Solution:

Chemical equation:

NaBr + KCl  → NaCl  + KBr

Number of moles sodium bromide:

Number of moles = Mass /molar mass

Number of moles = 25.0 g / 102.9 g/mol

Number of moles = 0.24 mol

Now we will compare the moles of NaCl with NaBr  .

                  NaBr         :               NaCl

                    1               :               1

                 0.24           :            0.24

Theoretical yield of sodium chloride:            

Mass  = moles × molar mass

Mass = 0.24 mol ×  58.5 g/mol

Mass =  14.04 g

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2