Aplatinum ball with a mass of 100 g is removed from a furnace and dropped into 400 g of water at 0 ◦c. if the equilibrium temperature is 10◦c and the specific heat of platinum is 130 j/kg◦c, what was the temperature of the furnace?

1,298 °C was the temperature of the furnace.

Explanation:

Heat lost by platinum will be equal to heat gained by the water

Mass of platinum =

Specific heat capacity of platinum=

Initial temperature of the iron =

Final temperature = =T  = 10°C

Mass of water=

Specific heat capacity of water=

Initial temperature of the water =

Final temperature of water = =T  = 10°C

On substituting all values:

we get, = 1,298°C

1,298 °C was the temperature of the furnace.

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).

10 years is the answer