Asample of solid iron is heated with an electrical coil. if 85.7 joules of energy are added to a 14.3 gram sample initially at 24.7 °c, what is the final temperature of the iron?

The final temperature of the iron is:- 38.0 °C

Explanation:

The initial temperature = 24.7 °C

Let Final temperature = T °C

Using,

Q = m C ×ΔT

Where,  

Q is the heat absorbed by the iron = 85.7 J

C gas is the specific heat of the iron = 0.45 J/g  °C

m is the mass of iron = 14.3 g

ΔT is the change in temperature. ( T - 24.7 ) °C

Applying the values as:

Q = m C ×ΔT  

85.7 J = 14.3 g × 0.45 J/g  °C  × ( T - 24.7 ) °C

Solving for T, we get that:-

T = 38.0 °C

The final temperature of the iron is:- 38.0 °C