Light of wavelength 570.00 nm is incident normally on a diffraction grating, and the third‑order maximum is observed to be 24.0∘ from the normal. how many slits per millimeter are marked on the grating?

Answer : The number of slits per millimeter marked on the grating are 238 slits/mm.

Explanation :

First we have to calculate the slit separation.

Formula used for a diffraction grating when maxima occur:

where,

d = slit separation = ?

a = angle =

= wavelength = 570.00 nm

n = order = 3

Now put all the given values in the above formula, we get:

Conversion used :

Now we have to calculate the number of slits per millimeter.

Therefore, the number of slits per millimeter marked on the grating are 238 slits/mm.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

well in order to answer this question you have to provide more information < 3