Calculate the freezing point of a solution containing 25 grams of kcl and 2750.0 grams of water. the molal freezing point depression constant (kf) for water is 1.86 ∘c/m.1.23 oc-0.45 oc+0.45 oc-0.23 oc+0.23 oc

-0.45 °C

Explanation:

The freezing point depression can be calculated using the formula:

Where ΔT is the change of the freezing point temperature (from 0°C of pure water), Kf is 1.86 °C/m, b is the molality, and i is 2 (in this case with KCl).

All data required is given except for b, so we calculate the molality:

25 g KCl ÷ 74.55g/mol = 0.3353 mol KCl

2750 g water ⇒ 2750/1000 = 2.75 kg water

Now we calculate ΔT:

So the freezing point of the solution is [0°C - 0.45°C] = -0.45 °C

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.