Express the concentration of a 0.0350 m aqueous solution of fluoride, f − , in mass percentage and in parts per million (ppm). assume the density of the solution is 1.00 g/ml. a. number in percentage %
b. number in ppm .

Answer :

(a) The mass percentage is 0.0665 %

(b) The concentration in ppm is 665 ppm.

Explanation :

Part (a) :

As we are given that, 0.0350 M aqueous solution of fluoride ion that means 0.0350 moles of fluoride ion present in 1 L of solution.

First we have to calculate the mass of fluoride ion.

Molar mass of = 19 g/mole

Now we have to calculate the mass of solution.

Mass of solution = Density of solution × Volume of solution

Density of solution = 1.00 g/mL

Volume of solution = 1 L = 1000 mL

Mass of solution = 1.00 g/mL × 1000 mL

Mass of solution = 1000 g

Now we have to calculate the mass -percentage.

Thus, the mass percentage is 0.0665 %

Part (b) :

Parts per million (ppm) : It is defined as the mass of a solute present in one million parts by the mass of the solution.

Now we have to calculate the concentration in ppm.

Thus, the concentration in ppm is 665 ppm.

it's filtration, but this is an assumption so my apologies if i got this

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .