What is the ph of a sodium formate solution prepared by adding 0.680 grams of sodium formate to 100.0 ml of water at 25.0°c? the ka at 25.0 °c for formic acid is 1.8 x 10-4. enter your answer with two decimal places.

Answer : The pH of the solution is, 8.38

Solution :  Given,

Concentration (c) = 0.11 M

Acid dissociation constant =

First we have to calculate the moles of sodium formate.

Now we have to calculate the concentration of formic acid.

Concentration of formic acid = Concentration of sodium formate =

Now we have to calculate the base dissociation constant.

The equilibrium reaction for dissociation of (weak base) is,

initially conc.         0.1                             0             0

At eqm.              (0.1-x)                            x             x  

First we have to calculate the value of 'x'.

Formula used :

Now put all the given values in this formula ,we get:

By solving the terms, we get

Thus, the concentration of hydroxide ion is:

Now we have to calculate the pOH.

Now we have to calculate the pH.

Therefore, the pH of the solution is, 8.38

is there multiple choice answers?

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.