25 points!

phosphoric acid reacts with sodium hydroxide: h3po4(aq) + 3naoh(aq) > na3po4(aq) + 3h2o(l)if 7.50 mol h3po4 is made to react with 15.0 mol naoh, identify the limiting reagent. show all work!

Sodium hydroxide (NaOH) is the limiting reactant

Explanation:

Step 1: Data given

Number of moles of NaOH = 15.0 mol

Number of moles of H3PO4 = 7.50 mol

Molar mass of NaOH = 40 g/mol

Molar mass of H3PO4 = 98 g/mol

Step 2: The balanced equation:

H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

Step 3: Calculate the limiting reactant

For 1 mole of H3PO4, we need 3 moles of NaOH

NaOH is the limiting reactant. It will completely be consumed. (15 moles)

H3PO4 is in excess, there will react 15.0 / 3 = 5 moles

There will remain 7.5 - 5.0 = 2.5 moles

There will be produced 15.0/3 = 5.0 moles of Na3PO4

There will be produced 15.0 moles of H2O

Sodium hydroxide (NaOH) is the limiting reactant

i believe it is a.) released into

explanation:

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.