Identify the species oxidized. 2 al3+(aq) + 2 fe(s) → 2 al(s) + 3 fe2+(aq)

3Fe(s)  → 3Fe²⁺ + 6e⁻

The oxidized is the Fe

Explanation:

2Al³⁺ (aq) + 3Fe(s) → 2 Al(s) + 3Fe²⁺(aq)

In this case, the oxidized is the Fe, where in the reactant side it acts with 0 in the oxidation number and in products side it acts with +2.

As the oxidation number was increased, this is the oxidation.

It has lost electrons.

3Fe(s)  → 3Fe²⁺ + 6e⁻

All the elements in ground state acts with 0 in oxidation number (solids)

Notice that in the main reaction, in reactant side Fe, must have 3 in Stoichiometry because the reaction is unballanced.

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

< 3

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j