Use the equation 2cu+o2 —> 2cuo to find how many grams of copper react to form 3.64 mol cuo.

231.31 g

We are given;

2Cu+O2 → 2CuO

We are required to determine the mass of copper that would react.

2 moles of Cu reacts with 1 mole of oxygen to yield 2 moles of CuO

Moles of Cu = moles of CuO

Thus, moles of Cu = 3.64 moles

But, Mass = Number of moles × atomic mass

Atomic mass of copper = 63.546

Thus,

Mass of Cu = 3.64 moles × 63.546 g/mol

                   = 231.31 g

Thus, 231.31 g of copper will react to produce 3.64 moles of CuO

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml