The equilibrium constant, kc, for the following reaction is 1.29×10-2 at 600k.

cocl2(g) 7e50f1f7-d29b-4777-b1ee-365a063b4be 8.gifco(g) + cl2(g)

if an equilibrium mixture of the three gases in a 17.7 l container at 600k contains 0.461 mol of cocl2(g) and 0.207 mol of co, the equilibrium concentration of cl2 is m

.

consider the following reaction:

cocl2(g) 7e50f1f7-d29b-4777-b1ee-365a063b4be 8.gifco(g) + cl2(g)

if 0.226 moles of cocl2(g), 0.536 moles of co, and 0.575 moles of cl2 are at equilibrium in a 17.1 l container at 658 k, the value of the equilibrium constant, kc, is .

An experimental procedure requires a 10 ml of acid to be dissolved

Using the thermodynamic information in the aleks data tab, calculate the standard reaction free energy of the following chemical reaction: →+p4o10s6h2ol4h3po4s round your answer to zero decimal places.

Imagine that a new planet is discovered with two moons of equal mass: moon a and moon b. the mass of the new planet is greater than the combined mass of its moons. moon a is farther away from the new planet than moon b. what is the planet's gravitational pull on moon a compared to the planet's gravitational pull on moon b? the planet's gravity repels moon a with a greater force than it repels moon b, which is why moon a is farther away. the gravitational pull on moon b is greater than on moon a because moon b is closer to the new planet than moon a. the gravitational pull on moon b is greater than on moon a because moon b is farther away from the new planet than moon a. the gravitational pull on moon a is the same as the gravitational pull on moon b because distance does not affect the planet's gravity.