Amole of a gas at stp has a volume of 22.4 l. if the volume increases to 29.1 l and the pressure is changed to 813 torr, calculate the new temperature.

379.39K

Explanation:

We use the form of the general gas equation below:

P1V1/T1 = P2V2/T2

Given: p1 = standard pressure = 760mmHg= 760 torr. Torr is the same thing as mmmHg

P2 = 813 torr

T1 = standard temperature = 273k

T2 = ?

V1 = 22.4L

V2 = 29.1L

Rearranging the equation :

T2 = P2V2T1/P1V1

Substituting the values in the equation:

T2 = (813 * 29.1 * 273)/ (760 * 22.4)

T2 = 379.39K

the formula would be mgso4

mgso[subscript]4

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